4-28.
Sketch a Carnol cycle for an ideal gas on a (a) u-v diagram, (b) u·T diagram,
(c)
u-h
diagram, (d) p. T diagram.
ANSWER:
u-h
diagram
p. T
diagram.
4-30. A
Carnot engine is operated between two heat reservoirs at temperatures of 400 K
and 300
K. (a) If the engine reoeives 1200 Cal from the reservoir at 400 K in each
cycle,
how many
Calories does it reject to the reservoir at 300 K? (b) If the engine is
operated as
a
refrigerator (i.e., in reverse) and receives 1200 Cal from the reservoir at300
K, how many
Calories
does it deliver 10 the reservoir at 400 K? (c) How much work is done by the
engine
in each
case?
ANSWER:
a) given
the heat that received by the engine at the host side is QH =
5024,16 Kj and determine the that discarded at the cold reseivor Qc. By
knowing TH, TC and
QH we get
QC = -QH
Given
values for TH, TC, and QH into Eg. (1) to get QC
QC = -5024,16 Kj
= -3748, 12 Kj
= 900 Cal
(b) we
know that TH = 400 K , TC
= 300 K and QH = 5024, 6 Kj.
QH = QC
QH
= 5024,16 Kj
= 6698,879998 Kj
= 1600 Cal
(c)
in part (a) we calculate QC and by knowing QC we can use
the Eq. to find W by,
W
= | QH – QC | ………(2)
We
have QH and QC, so
if we plug these values in Eq. (2) we
get
W
= | QH | - | QC |
W
= 1200 Cal – 900 Cal
= 300 Cal
4. 31. (a)
Show that for Camel engines operating between the same high temperature reservoirs
and different low temperature reservoirs, the engine operating over rhe largest
temperature
difference has the greatest efficiency. (b) Is the more effective way to
increase
the efficiency
of a Carnol engine to increase the temperature of the hotter reservoir,
keeping
the temperature of the colder reservoir constant, or vice versa? (c) Repeal
pans
(a) and
(b) to find the optimum coefficient of performance for a Carnot refrigerator.
ANSWER:
(a) Ta1 = Tb1 = T
Ta2
= ¾ T
Tb2
= ½ T
Carnor
machine b memiliki perbedaan suhu yang lebih besar dari Carnot machine a
µa
= ( 1 – T2/ T1 ) x 100%
=
( 1 – ¾ T / T ) x 100%
=
¼ x 100 %
= 25%
µb = ( 1 – T2/ T1 ) x 100%
=
( 1 – ½ T / T ) x 100%
= ½ x 100%
=
50%
(b) by
lowering the high temperature
(c)
koefisien kinerja (kp)
Kpa =
=
=
=
3
Kpb
=
=
=
=
1
Kpb
> Kpa (Semakin
besar perbedaan suhu semakin kecil Kp)
4-34.
Calculate the efficiency and the coefficient of performance of the cycles shown
in
(a)
Problem 3-26, and (b) Problem 3- 27.
ANSWER :
Proses
a-b-c
Q1 =
80J
W =
30J
Proses
a-d-b
ΔW = Wacb – Wadb
=
30J – 10J = 20J
Q2 = Q1 – W
=
80J – 20 J = 60J
µ =
=
= 25%
Kp
=
= 60J / 20J
= 3
µ and Kp
from problem (b) 3.27
.
mengompres a – c adiabatic membutuhkan 1000J
.
mengompres b – c membutuhkan panas 1500J keluar system
µ =
(1000J / 1500J) x 100%
= 66.7%
Kp
= 1500J / 1000J
= 1.5
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